Question Pattern:
* 5 sections
* 8 questions each (40 q totally)
* 60 minutes
* 5 different sets of question papers
* 1 Mark each
* 0.25 negative marking
Question Booklet Types:
CTS_BLACK
vocabulary,strings,dominoes,functions,coding
(each section 8 ques)
CTS_BROWN
word series,numerical series,functions,figures,verbal
(each section 8 ques)
CTS_VIOLET
functions,strings,bricks,jigsaw puzzle,cryptic clues
(each section 8 ques)
CTS_RED
1. 8 functions
2. 4 cryptic clues ,4 anagrams
3. 4 tetris figures, 4 bricks
4. 8 strings
5. 4 jigsaw puzzles 4 number series
Instructions
1. All answers provided in these sets may not be
correct. So Please check.
2. do read old papers. few questions of 2002 came from
these old sets
Interview
* puzzles
* technical
Brown
2002 Placement Paper Set
There were
different papers for different sessions.
The paper had 5 sections, 5 * 8 = 40 Q's. totally.
Section 1 : Functions.
Q: 1 - 8
Certain functions were given &
based upon the rules & the choices had to be made
based on recursion. This is time consuming, but u can do
it. Try to do it at the end. start from the last
section.
L(x) is a function defined. functions can be defined as
L(x)=(a,b,ab) or (a,b,(a,b),(a,(b,b)),a,(b,b))....
two functions were given A(x) & B(x) like
if l(x)=(a,b,c) then A(x)=(a) & B(x)=(b,c)
i.e., A(x) contains the first element
of the function only.
& B(x) contains the remaining, except the first
element.
then the other two functions were defined as
C(x) = * if L(x) = ()
A(x) if L(x) = () & B(x) != ()
C(B(x)) otherwise
D(x) = * if L(x) = ()
** if B(x) = ()
A(x) if L(x) != () & B(x) != ()
D(D(x)) otherwise
Now the Questions are,
1 : if L(x) = (a,b,(a,b)) then C(x) is ?
(a): a (b): b (c): c (d): none
2 : if L(x) = (a,b,(a,b)) then find D(x)
same options as above
3 : if L(x) = (a,b,(a,b),(b,(b))) find C(x)
4 : -----------~~~~~~~~---------- find D(x)
5 : if L(x) = (a,(a,b),(a,b,(a,(b))),b) then find c(x)
6 : -----------~~~~~~~~---------- find D(x)
7 : if L(x) = (a,b,(a,b)) then find C(D(x))
8 : -----------~~~~~~~~---------- find D(C(x))
Section 2 :
Word series
Q's : 9 - 16
This is one of the easiest section.
Try to do it at first.
If S is a string then p,q,r form the
substrings of S. For eg, if S=aaababc & p=aa q=ab r=bc
then on applying p->q on S is that ababaabc. Only the
first occurance of S has to be substituted. If there is
no substring of p,q,r on s then it should not be
substituted.
If S=aabbcc, R=ab, Q=bc. Now we define an operator
R Q when operated on S, R is replaced by Q,
provided Q is a subset of S, otherwise R will be
unchanged.
Given a set S= ………., when
R Q, P== 672; R, Q
 P operated successively on S, what will be
new S?
9. If s=aaababc & p= aa q=ab r=bc
then applying p->q, q->r & r->p will give,
(a) aaababc (b) abaabbc (c) abcbaac (d) none of the
a,b,c.
10. If s=aaababc & p= aa q=ab r=bc
then applying q->r & r->p will give,
11. If s=abababc & p= aa q=ab r=bc
then applying p->q, q->r & r->p will give,
12. If s=abababc & p= aa q=ab r=bc
then applying q->r & r->p will give,
13. If s=aabc & p=aa q=ab r=ac
then applying p->q(2) q->r(2) r->p will give,
(2) means applying the same thing twice.
14. Smiliar type of problem.
15. s=abbabc p=ab q=bb r=bc then to
get s=abbabc which one should be aplied.
(a) p->q,q->r,r->p
16. Is=abbabc p=ab q=bb r=bc
then to get s=bbbcbabc which one should be applied.
Let us consider a set of strings such
as S=aabcab. We now consider two more sets P and Q which
also contain strings. An operation P->Q is defined in
such a manner that if P is a subset of S, then P is to
be replaced by Q. In the following questions, you are
given various sets of strings on which you have to
perform certain operations as defined above. Choose the
correct alternative as your answer.
Below are some questions from
old questions papers.
13. Let S=abcabc, P=bc, Q=bb and R=ba. Then P->Q,
Q->R, R->P changes S to
(A) ............ (B) abcabc (C) ............ (D) none of
A,B,C
14. Let S=aabbcc, P=ab, Q=bc and
R=cc. Then P->Q, Q->R, R->P changes S to
(A) ababab (B) ............ (C) ............ (D) none of
A,B,C
15. Let S=bcacbc, P=ac, Q=ca and R=ba.
Then P->Q, Q->R, P->R changes S to
(A) ............ (B) ............ (C) bcbabc (D) none of
A,B,C
16. Let S=caabcb, P=aa, Q=ca and R=bcb.
Then P->Q, P->R, R->Q changes S to
(A) ............ (B) ............ (C) ............ (D)
none of A,B,C
Section 3 :
Numerical Series
Q's : 17 - 24
This is little bit tough. proper
guesses should be made. Find these problems in R. S.
Aggarwal's verbal & non verbal reasoning.
17. 2,20,80,100, ??
(a) 121, (b) 116 (c) (d) none
18. 10,16,2146,2218, ??
19. 1 1 0 2 2 1 1 ---> 0 0 1 0 0 2 2
1 0 1 1 0 0 1 ---> 2 1 2 2 1
1 2
then
2 2 1 1 0 1 1 ---> ????
Ans: 0 0 2
2 1 2 2
Similar Questions.
Section 4 :
Figures
Q's : 25 - 32
Mainly Pattern Recognization in
terms of set of pictures, is asked.
25.
^ ^ ^
| -> <- | -> |
^ : ^ :: ^ : ?
| -> <- | <- |
Ans:
^
| <-
^
| ->
All probems are very easy.
Some are mirror images, some are rotated clockwise/anti
clockwise etc.
Section 5 : Verbal
Q's : 33 - 40
If u have a very good vocabulary
then this section is managable. Two words together
forming a compound words were given. The questions
contain the second part of the compound word. The first
word of the compuond word has to be guessed. Then its
meaning has to be matched with the choices.
Exapmle:-
If the word is "body" then its meaning of its
first part can be head, god etc as
block head
main stream
star dust etc.
33. _____ head
(a) purpose (b) man (c) obstacle (d) none
Ans: c (for
blockhead)
34. dust _____
(a) container (b) celestial body (c) groom (d) none
Ans: c (for star
dust)
35. stream _____
(a) mountain (b) straight (c) lake (d) none
Ans: a
36. crash _____
(a) course (b) stock (c) book (d) none
Red 2002
Placement Paper Set
Section 1 :
Series Transformation
1) If 102101->210212 then
112112->?
2) if 102101-> 200111 then 112112->?
3) If 102101->101201 then 112112->?
Tips:
The 1st one all change 0->1, 1->2, 2->1
The 2nd on alternate do not change
The 3rd it is just reverse of the original string.
Section 2
: Brick Operations
1. Target = 127: Brick= 24,17,13: Operation available=
+,/,*,-
a)21,6,7
b)20,6,7
c)240,8,7
d)20,6,39
Ans: b (As
20*6+7=127)
2. Target = 102
Ans: 6,17,2,1
3. Target = 41: Bricks =
25,22,16,5,1: Operations available= +,/,*,-
a) 25 22 16 5 b) 25 22 16 1 c) 25 22 5 1 d) 25 16 5 1
Section 3
: Cryptic Sentence. Form Words
A sentence is there. A cryptical
clue is hidden in the sentence. Find out answer from the
options.
1. A friend in rome
a) aerodrome b) palindine c) palindrome d) condome
Ans: palindrome
2. Rowed them across
a) crosswiz b) acropolis c) acroword d) crossword
Ans:
crossword/crossover
3. Cuticle cutting the filly glass
a) cubicle b) uphilly c) cutglass d) cutlass
Ans: cutlass
4. Hat jumps upward in a water closet
a) watch b) witch
Ans: watch
Section 4 :
Anagram Nouns forming corresponding Adjectives
Some nouns are jumbled on
,you have to rearrange, look for a suitable adjective.
Then Make a phrase.
1. shore
a) aegean b) indian c) trojan d) spartan
Ans: trojan
2. Sire
a) dutch b) rome c) herculean d) mercurial
Ans: mercurial
3. ourcage
a) english b) rome c) dutch d) spartan
Ans: spartan
4) lips
a) english b) freudian/french c) dutch d) spartan
Ans: freudian/french
Section 5 :
Puzzles
Jigsaw puzzle as given in the book
by Edgar Thorpe, of TMH Publications
Section 6 :
Functions
Section 7 :
String Questions
x , y -> strings of G st there is
at least one G in x and y such that
xoxy valid
xoy->xoxy invalid
Now Find valid & invalid strings?
Section 8 :
Figures
There were seven figures given on the
basis of a theme. The 10 questions that followed
showed patterns which were formed due to combination of
the seven basic figures.
NOTE: The intersecting part of the
combined figure always gets subtracted from the total
combination |