1. In the month of october in a
year has exactly four mondays and four fridays, find
what day of week wiil be on the 20th of November of
that year.
Ans: 20th
November was a wednesday.
2. Six persons A,B,C,D,E & F
went to solider cinima. There are six conseutive
seats. A sits in one of the seats followed by B,
followed by C and soon. If a taken one of the six
seats , then B should sit adjacent to A. C should sit
adjacent A or B. D should sit adjacent to A, B,or C
and soon. How many possibilities are there?
Ans: 32 ways.
3. (i) If alpha = gamma then beta
is not = epsilon.
(ii) If alpha - beta = beta - gamma then alpha
>gamma.
(iii) Alpha > gamma > theta, write all the five
in descending order.
4. In mathematica country
1,2,3,4....,8,9 are nine cities. Cities which form a
no. that is divisible by 3 are connected by air
planes. (e.g. cities 1 & 2 form no. 12 which
divisible by 3 then 1 is connected to city 2). Find
the total no. of ways you can go to 8 if you are
allowed to break the journies.
Ans: 5.
5. ABCDE are sisters. Each of them
gives 4 gifts and each receives 4 gifts No two sisters
give the same combination ( e.g. if A gives 4 gifts to
B then no other sisters can give four to other one.)
(i) B gives four to A.
(ii) C gives 3 to E.
How much did A,B,C,E give to D?
Ans: Donor no
of gifts A 1 B - C 1 D 2
6. There are some bulbs,which are
numbered from 1 to 100.all the bulbs are in on
conditions. The following operations are performed:-
1. Those bulbs number which are
divisible by 2 are switched OFF.
2. Those bulbs numbered which are divisible by 3 are
switched ON (which are already OFF) and OFF bulbs are
switched ON.
3. Similarly bulbs numbers divisible by 4 are either
switched ON or OFF depending upon there previous
condition.
4. This procedure is adopted till 100th bulb.
At the end there were how many
bulbs which were in ON condition?
Ans: 10 ( only
perfect squares ).
7. There are different numbers
related with A,B,C,D,E.such that, AB*CD=EEE.
E*CD-AB=CC.
Find AB*D.
Ans: BE.
8. Find the total no of 10 digits
whose sum is 4.
9.Four musician problem(refer GRE
BARRONS).
10.GRE BARRONS problem -->
Problem number 25 to 28 page no. 4.
11. Logical reasoning
tactics practice puzzle poetry.
1) Henny, Axie, Amie are friends.
Conditions:-
a) Herry or Axies is the oldest.
b)If Axie is the oldest, Amie is the youngest.
Who is the youngest & who is
the oldest?
Ans: Amie is
the youngest, Axie is oldest.
2) A, B, C are 3 girls and there
are 770 Apples. For every 4 Apples, A takes,B takes 3.
For ever 6 Apples, C takes 7 Apples?
Ans:
261:145:303.
3) T, U, V are 3 friends digging
groups in fields. If T & U can complete i groove
in 4 days &, U & V can complete 1 groove in 3
days & V & T can complete in 2 days. Find how
many days each takes to complete 1 groove
individually.
Ans: 24 days.
4) 4 mathematician has x apples. If
he arranges them in rows of 3 one will be left. The
same is the case with 5,7,9 apples. But when he
arranged them in rows of 11, non will be left. Find
the no. of apples.
Ans: 946.
(Hint: 11*6 11*11 11*16 11*21 =2E......11*76 =3D946).
5) H starts running after T reaches
1/5th they must when H reach 1/6th, if H wants win at
what speed H should be run? Note: One circle is there,
you show this type of problem.
6) There are 4 monthers, 4
daughters and the colour of their dresses, and they
are aged 1, 2, 3 & 4. Details of the dresses are
given & then it asked about the remaining dresses.
7) There are 5 levels of dolls and
each of different colors & condition are given.
Note: This type of problem also refer.
8) 5 student A, B, C, D, E. One
student knows 5 languages. Like that up to one
langauge. Conditions:-
*) Spanish is most popular langauge.
*) 3 persons knows Porchigese.
*) B & C normally speak English, but when D
gathered, they switched to Spanish because that is
only common between the three.
*) Only langauge common between A, B, E is French.
*) Only langauge common between C & E is Italian.
Interview
Section
No. of
candidates appeared : 220.
For the Interview : 90.
1. An escalator is descending at
constant speed. A walks down and takes 50 steps to
reach the bottom. B runs down and takes 90 steps in
the same time as A takes 10 steps. How many steps are
visible when the escalator is not operating.
150.
2. Every day a cyclist meets a
train at a particular crossing. The road is straignt
before the crossing and both are travelling in the
same direction. Cyclist travels with a speed of 10
Kmph. One day the cyclist comes late by 25 min. and
meets the train 5km before the crossing. What is the
speed of the train.
60 kmph.
3. Five persons muckerjee, misra,
iyer, patil and sharma, all take then first or middle
names in the full names. There are 4 persons having
first or middle name of kumar, 3 persons with mohan, 2
persons with dev and 1 anil.
-- Either mukherjee and
patil have a first or middle name of dev or misra and
iyer have their first or middle name of dev.
-- Of mukherkjee and misre, either both of them have a
first or middle name of mohan or neither have a first
or middle name of mohan.
-- Either iyer of sharma has a first or middle name of
kumar but not both.
Who has the first or middle name of
anil?
Today is
Mukherjee.
4. Reading conprehension.
5. A bird keeper has got P pigeon,
M mynas and S sparrows. The keeper goes for lunch
leaving his assistant to watch the birds.
a. Suppose p=10, m=5, s=8, when the
bird keeper comes back, the assistant informs the x
birds have escaped. the bird keeper exclaims oh no!
all my sparrows are gone. How many birds flew away?
b. When the bird keeper come back,
the assistant told him that x birds have escaped, the
keeper realised that at least two sparrows have
escaped. What is minimum no of birds that can escape?
6. Select from the five
alternatives A, B, C, D, E at the end of each
question, two conditions will be given. The choices
are to filled at follows:-
a. If a definite conclusion
can be drawn from condition 1.
b. If a definite conclusion can be drawn from
condition 2.
c. If a definite conclusion can be drawn from
condition 1 and 2.
d. If a definite conclusion can be drawn from
condition 1 or 2.
e. No conclusion can be drawn using both conditions.
1. Person 1 says N<5.
Person 2 says n>5.
Person 3 says 3N>20.
Person 4 says 3n>10.
Person 5 says N<8.
What is value of N?
a) 1. Number of persons who speak
false being less than no of persons who tells the
truth.
2. Person 2 is telling the truth.
b) 1. Number of persons telling the
truth is greater than no of persons telling lies.
2. Person 5 is telling the truth.
7. There are N coins on a table.
There are two players A & B. You can take 1 or 2
coins at a time. The person who takes the last coin is
the loser. A always starts first.
1. If N=7,
a) A can always win by taking two
coins in his first chance.
b) B can win only if A takes two coins in his first
chance.
c) B can always win by proper play.
d) None of the above.
2. A can win by proper play, if N
is equal to
a) 13
b) 37
c) 22
d) 34
e) 48
Ans. E.
3. B can win by proper play, if N
is equal to
a) 25
b)26
c) 32
d) 41
e) none
4. if N<4, can A win by proper
play always?
8. Two turns have vertain peculiar
characteristics. One of them always lies on Monday,
Wednesday, Friday. The other always lies on Tuesdays,
thursdays and saturdays. On the other days they tell
the truth. You are given a conversation.
Person A -- Today is sunday and my
name is anil.
Person B -- Today is tuesday and my
name is Bill. What is today?
Today is
tuesday.